regex - regexp: how to remove the beginning of the path -


i have regular expression parse gcc compilation output:

^(..[^:]*):([0-9]+):?([0-9]+)?:? (.*)$

the first sub expression - ^(..[^:]*) mark file error occurs.

for example, input:

main.c:1156:13: error: invalid storage class

it mark

main.c

and input:

folder/main.c:1156:13: error: invalid storage class

it mark

folder/main.c

how can change first sub expression mark file name without full path?

i suggest replacing (..[^:]*) (?:[^\r\n:]*/)?([^:\r\n]*):

^(?:[^\r\n:]*/)?([^:\r\n]*):([0-9]+):?([0-9]+)?:? (.*)$  ^^^^^^^^^^^^^^^^^^^^^^^^^^

see regex demo

the change part matches:

  • (?:[^\r\n:]*/)? - 1 or 0 occurrences of:
    • [^\r\n:]* - 0 or more chars other :, cr , lf , then
    • / - / char
  • ([^:\r\n]*) - group 1: 0 or more chars other :, cr , lf

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