scala - Get a string from an object in the template -

imagine have case class so:

   case class team(_id: option[bsonobjectid], name: string = "", city: string = "", country: string = "") 

and passing template (in play 2.5/scala/reactivemongo 0.11.14) this:

   @(teams : seq[models.team])     ...        @for(team <- teams){             <tr>                 <td>@team._id</td>                 <td>@team.name</td>                 <td>@team.city</td>                 <td>@team.country</td>             </tr>       }     ... 

i need @team._id (which type option[bsonobjectid]) string - bsonobjectid characters string. have been trying declare reusable values documented here can't seem right. ordinarily use flatmap isn't working expected within template. help!

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following on seems should use method within case case class @marcospereira suggested. little stuck (unsurprisingly!) on syntax in regex expression. trying make string - bsonobjectid("59654f33b17946eac2323b3e") 59654f33b17946eac2323b3e. have:

def idasstring = _id.flatmap(bson => """\".*?(")""".r.findfirstin(bson.tostring)).getorelse("") 

but returns quotation marks, e.g. "59654f33b17946eac2323b3e". mentioned don't want - can can't quite syntax right.

you can like:

case class team(_id: option[bsonobjectid] = none, name: string = "", city: string = "", country: string = "") {      def idasstring(): string = _id.getorelse("")  } 

and then:

<td>@team.idasstring()</td> 

notice i've add none default _id. can have "view helper" this:

package helpers  object optionviewhelpers {   def optionvaluetostring(o: option[_]): string = o match {     case some(v) => string.valueof(v)     case _ => ""   } } 

and view:

@import helpers._  <td>@{optionviewhelpers.optionvaluetostring(team._id)}</td> 

the advantage here can reuse in other scenarios.