regex - regexp: how to remove the beginning of the path -

i have regular expression parse gcc compilation output:

^(..[^:]*):([0-9]+):?([0-9]+)?:? (.*)$ 

the first sub expression - ^(..[^:]*) mark file error occurs.

for example, input:

main.c:1156:13: error: invalid storage class 

it mark

main.c 

and input:

folder/main.c:1156:13: error: invalid storage class 

it mark

folder/main.c 

how can change first sub expression mark file name without full path?

i suggest replacing (..[^:]*) (?:[^\r\n:]*/)?([^:\r\n]*):

^(?:[^\r\n:]*/)?([^:\r\n]*):([0-9]+):?([0-9]+)?:? (.*)$  ^^^^^^^^^^^^^^^^^^^^^^^^^^ 

see regex demo

the change part matches:

• (?:[^\r\n:]*/)? - 1 or 0 occurrences of:
  • [^\r\n:]* - 0 or more chars other :, cr , lf , then
  • / - / char
• ([^:\r\n]*) - group 1: 0 or more chars other :, cr , lf